Workshop CHE 168
Answers for
Problem Set #4
 
 

1.

(a) - (1/2)Rate(O₃) = +(1/3)Rate(O₂)
(b) 4.0 x 10^-5 M/s

2.

(a) 8.4 x 10^-7 M/s
(b) 2.1 x 10^-7 M/s

3.

(a) Rate(C) = k[A]²[B]⁰
(b) 4.0 x 10^-3 M^-1s^-1
(c) 1.0 x 10^-5 M/s

4.

(a) - Rate(NO) = k[NO]²[O₂]
(b) 7.11 x 10³ M^-2s^-1

5.

(a) + Rate(NOBr) = k[NO]²[Br₂]
(b) 2.4 x 10⁴ M^-2s^-1
(c) 30 M/s

6.

(a) 1.6 x 10² kJ/mol
(b) 1.0 x 10^-5 s^-1

7.

(a) Rate = k[NO][Cl₂] {second order overall}
(b) The second step must be slow relative to the first step or rate-determining; also, the first step should probably be a rapid equilibrium.

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