Workshop CHE 166
Answers for
Problem Set #5
1.
a) Li+, OH-
b) NH4+, NO3-
c) Na+, CrO42-
d) K+, Cl-
e) Al3+, SO42-2. conduct electricity
3.
a) I
b) I
c) S
d) S
e) I
f) S
g) S
h) I
I) S
j) I4.
a) W
b) S
c) S
d) W
e) N
f) S
g) N
h) W
I) S5.
a) W/base
b) W/acid
c) S/base
d) W/acid
e) S/acid
f) W/acid
g) S/base6. Ca(NO3)2
7. CaCl2
8. No reaction.
9. Ppt. of PbI2 will be formed.
10. 3; [1,3,3,2]
11.
a) Ppt. of Ag2CO3 formed
b) Ppt. of BaCO3 formed
c) No Reaction
d) H2S (aq) formed; a weak electrolyte
e) Pb(C2H3O2)2 (aq) formed; a weak electrolyte
12. +7
13. - 2
14. +6
15. A Group IV element; thus, +4
16. 6 e- + 14 H+ (aq) + Cr2O72- (aq) ® 2 Cr3+ (aq) + 7 H2O (l)
17. 16 H+ (aq) + 2 MnO4- (aq) + 10 Br- (aq) ® 5 Br2 (aq) + 2 Mn2+ (aq) + 8 H2O (l)
MnO4-: Oxidizing agent and substance reduced.
Br-: Reducing agent and substance oxidized.
18. 6 H2O (l) + 3 H+ (aq) + 4 As (s) + 3 ClO3- (aq) ® 3 HClO (aq) + 4 H3AsO3 (aq)
ClO3-: Oxidizing agent and substance reduced.
As: Reducing agent and substance oxidized.19. 2 Ag+ (aq) + H2O2 (aq) ® O2 (g) + 2 Ag (s) + 2 H+ (aq)
Ag+: Oxidizing agent and substance reduced.H2O2: Reducing agent and substance oxidized.
20. 2 e- + H2O (l) + ClO- (aq) ® Cl- (aq) + 2 OH- (aq)
21. 3 Bi(OH)3 (s) + 3 SnO22- (aq) ® 3 SnO32- (aq) + 2 Bi (s) + 3 H2O (l)
Bi(OH)3: Oxidizing agent and substance reduced.
SnO22-: Reducing agent and substance oxidized.
22. H2O (l) + 2 MnO4- (aq) + I- (aq) ® IO3- (aq) + 2 MnO2 (s) + 2 OH- (aq)
MnO4-: Oxidizing agent and substance reduced.
I -: Reducing agent and substance oxidized.